Answer:
See explanation.
Explanation:
Hello there!
In this case, for the required chemical reactions, we proceed as follows, by considering that the left-handed elements stand for the cations and the right-handed ones for the anions:
1:
1. [tex]Na_2CO_3(aq)\rightarrow 2Na^+(aq)+(CO_3)^{2-}(aq)[/tex]
2. [tex]FeBr_3(aq)\rightarrow Fe^{3+}(aq)+3Br^-(aq)[/tex]
3. [tex]Al_2(SO_4)_3(aq)\rightarrow 2Al^{3+}(aq)+3(SO_4)^{2-}(aq)[/tex]
2: In this case, we can represent the formula equation first according to the neutralization reaction:
[tex]3NaOH(aq)+H_3PO_4(aq)\rightarrow Na_3PO_4(aq)+3H_2O(l)[/tex]
Which is worded as: three molecules of aqueous sodium hydroxide reacts with one molecule of aqueous phosphoric acid to yield one molecule of aqueous sodium chloride and three molecules of liquid water.
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