Answer:
BDCEA
Step-by-step explanation:
A: area of the triangle = [tex]\frac{1}{2}bh = \frac{1}{2}(10)(4) = \frac{1}{2}(40) = 20 ft^{2} \\[/tex]
B: area of the rectangle + area of the triangle =[tex](5*6) + \frac{1}{2}(5)(6) = 30+15=45 ft^{2}[/tex]
C: area of the rectangle + area of the trapezoid = [tex](6*2) + \frac{1}{2}(b_{1} +b_{2})(h) = (6*2)+ \frac{1}{2}(2+5)(5) = 12+\frac{1}{2}(35) = 29.5 ft^2[/tex]
E: area of the triangle = [tex]\frac{1}{2}bh = \frac{1}{2}(14)(4) = \frac{1}{2}(56) = 28 ft^{2} \\[/tex]
D: area of the rectangle + area of the triangle = [tex](8*3) + \frac{1}{2}(8)(2) = 24+8=32 ft^{2}[/tex]
