Respuesta :
sin ( π / 3 - x ) =
= sin π/3 cos x - cos π/3 sin x = ( additional formulas )
= √3 / 2 cos x - 1/2 sin x =
= 1/2 ( √3 cos x - sin x )
Answer: B )
= sin π/3 cos x - cos π/3 sin x = ( additional formulas )
= √3 / 2 cos x - 1/2 sin x =
= 1/2 ( √3 cos x - sin x )
Answer: B )
Answer:
The Value of
[tex]Sin (\frac{\pi}{3}-x)=Sin(\frac{\pi}{3})*cos x - Cos(\frac{\pi}{3})* Sin x\\\\=\frac{\sqrt{3}}{2}*Cos x -\frac{Sin x}{2}\\\\=\frac{1}{2}[\sqrt{3}Cos x - Sin x][/tex]
Using the Sine Law
Sin (A-B)=Sin A *Cos B - Cos A * Sin B
as well as
[tex]Sin (\frac{\pi}{3})=\frac{\sqrt{3}}{2}, Cos (\frac{\pi}{3})=\frac{1}{2}[/tex]
Option B: [tex]\frac{1}{2}[\sqrt{3}Cos x - Sin x][/tex]