Answer: Molarity of the solution is 0.028 M.
Explanation:
Given : Moles of sucrose (solute) = 0.112 mol
Volume of solution = 4.0 L
Molarity is the number of moles of solute dissolved in a liter of solvent.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.112 mol}{4.0 L}\\= 0.028 M[/tex]
Thus, we can conclude that molarity of the solution is 0.028 M.