Answer:
1.41
Step-by-step explanation:
The maximum walking speed S, in feet per second, of an animal can be modeled by the equation S= √(gL), where g = 32ft/sec² and L is the length, in feet, of the animal's leg. To the nearest hundredth, how many times greater is the maximum walking speed of a giraffe with a leg of 6 feet than a hippopotamus with a leg of 3 feet?
Step 1: Calculate the maximum walking speed of a giraffe
The leg of a giraffe measures L = 6 ft.
Sg= √(g × Lg)
Sg= √(32 ft/s² × 6 ft) = 13.86 ft/s
Step 2: Calculate the maximum walking speed of a hippopotamus
The leg of a hippopotamus measures L = 3 ft.
Sh= √(g × Lh)
Sh= √(32 ft/s² × 3 ft) = 9.80 ft/s
Step 3: Determine how many times greater is the maximum walking speed of a giraffe than a hippopotamus
We will make the ratio Sg/Sh
Sg/Sh = (13.86 ft/s)/(9.80 ft/s) = 1.41
The maximum walking speed of a giraffe is 1.41 times greater than the maximum walking speed of a hippopotamus.
It is described as the comparison of two quantities to determine how many times one obtains the other. The proportion can be expressed as a fraction or as a sign: between two integers.
The leg of a giraffe measures L = 6 ft.
S(g)= √(g×L)
S(g) = √(32 ft/s² × 6 ft)
S(g) = 13.86 ft/s
The maximum walking speed of a hippopotamus:
The leg of a hippopotamus measures L = 3 ft.
S(h)= √(g×L)
S(h) = √(32 ft/s² × 3 ft)
S(h) = 9.80 ft/s
The ratio S(g) to S(h)
S(g)/S(h) = 13.86/9.80 = 1.41
S(g) = 1.41S(h)
Thus, the maximum walking speed of a giraffe is 1.41 times greater than the maximum walking speed of a hippopotamus.
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