Question

An iron wire has a length of 1.50 m and a cross sectional area of 0.450 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and a potential difference of 0.800 V is maintained across its length, determine the current in the wire (in A)

Answer 1

Answer:

2400A

Explanation:

R=pL/A

R-Resistance

p-Resistivity=10.0 x 10^-8

L-1.5m

A-Cross sectional Area=0.00045

R=10.0 x 10^-8 x 1.5 ÷ 0.00045

and=0.000333333

I-current

V-potential difference

I=V/R

0.800÷0.000333333

Ans=2400A