Answer:
445 fish per year
Explanation:
Given that
The carrying capacity is 2,200 fish
The maximum rate of increase of 1.0 per individual per year
The population is 1,580 fish
We need to find out the approximate population growth rate
We know that
dP ÷ dt = kP (1 - P÷ K)
where
K denotes the carrying capacity
k denotes the rate constant
dP ÷ dt denotes the change in the population per unit time
P denotes the population
Now put the values to the above formula
= 1 × 1,580 × (1 - 1,580 ÷ 2,200)
= 1 × 1,580 × (1 - 0.72)
= 445 fish per year
