Answer: The volume of given ball is 21 L.
Explanation:
Given : Pressure = 1.0 atm, no. of moles = 0.85 mol
Temperature = [tex]25^{o}C = (25 + 273) K = 298 K[/tex]
According to the ideal gas equation, formula used is as follows.
PV = nRT
where,
P = pressure
V = volume
n = no. of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the values into above formula as follows.
[tex]PV = nRT\\1.0 atm \times V = 0.85 mol \times 0.0821 Latm/mol K \times 298 K\\V = 21 L[/tex]
Thus, we can conclude that the volume is 21 L.
