The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.​

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Question:-

The age of Sita is five years more than Gautam's age. 5 years ago, the ratio of their ages was 3:2. Find their present ages.

Solution:-

The age of Sita = (x + 5) years.

And, the age of Gautam = x years.

Now,

5 years ago, the ratio of their ages was 3 : 2

[tex] \therefore [/tex] [tex] \bf \frac{3}{2} \: = \frac{x \: + \: 5}{x} [/tex]

Now by cross multiplying, we get,

3x = 2(x + 5)

3x = 2x + 10

3x - 2x = 10

x = 10

Hence, the age of Sita = (x + 5) = (10 + 5) = 15 years.

And, the age of Gautam = x = 10 years.

Now,

The present age of Sita = 15 + 5 = 20 years. (Answer)

And, the present age of Gautam = 10 + 5 = 15 years. (Answer)

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