A small lead pencil has a cylindrical base and a conical point.
r = 0.5cm
2 cm
15 cm
Find the slant height of the cone. (Use the Pythagorean theorem.) Round to the nearest tenth. (you don't need to type the unit)
Slant Height-
Find the surface area of the whole pencil. (round to the nearest tenth, Pi=3.14)
Area of the whole pencil=

A small lead pencil has a cylindrical base and a conical point r 05cm 2 cm 15 cm Find the slant height of the cone Use the Pythagorean theorem Round to the near class=

Respuesta :

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Answer:

  • slant height: 2.1 cm
  • pencil area: 51.12 cm^2

Step-by-step explanation:

The slant height (s) is the hypotenuse of the right triangle with legs of 2 cm and 0.5 cm.

  s^2 = 2^2 + 0.5^2 = 4 + 0.25

  s = √4.25 ≈ 2.0616 ≈ 2.1

The slant height is about 2.1 cm.

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The surface area of the whole pencil is the sum of the areas of the circular base, the lateral area of the cylindrical part, and the lateral area of the cone.

  A = πr^2 +2πrh +πrs

  A = πr(r +2h +s) = (3.14)(0.5 cm)(0.5 cm + 2×15 cm + 2.1 cm)

  A ≈ 51.12 cm^2

The area of the whole pencil is about 51.12 cm^2.

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