Question

A 4 kg box is at rest on a table. The static friction coefficient u, between the box and table is 0.30, and
the kinetic friction coefficient Hi is 0.10. Then, a 10 N horizontal force is applied to the box.

Answer 1

Answer:

The box will not move from its position.

Explanation:

First, we will calculate the static frictional force that is stopping the box to move from its position:

$f = \mu R = \mu W=\mu mg$

where,

f = static frictional force = ?

μ = coefficient of static friction = 0.3

m = mass of box = 4 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$f = (0.3)(4\ kg)(9.81\ m/s^2)\\f=11.77\ N$

Since the frictional force (11.77 N) is greater than the applied force (10 N).

Therefore, the box will not move from its position.