Question

What is the arc measure, in degrees, of ADC on circle P below?


70°


104°

Answer 1

Answer:

The answer is "$\overarc{ADC} = m\angle CPD + m\angle DPA = 186$"

Step-by-step explanation:

Please find the image of the question:

In the circle p:

$\to m\angle APB + m\angle BPC + m\angle CPD + m\angle DPA = 360^{\circ} \\\\\to 70 + 104 + m\angle CPD + m\angle DPA = 360\\\\\to m\angle CPD + m\angle DPA = 360 - 70 - 104 = 186$

Let P is in the center

$\to$ arc AD= $m\angle APD$

$\to$ arc DC = $m\angle CPD$  

$\to$ arc BC = $m\angle BPC$  

arc AB =

When D is on arc AC:

$\to$arc ADC =  arc AD  + arc DC  

$\to$arc ADC = $m \angle CPD + m\angle DPA = 186$