Determine what product will be produced at the negative
electrode for the following reaction:
2CuSO4 (aq) + 2H20 (1) -> 2Cu(s) + 2H2SO4(l) + O2(g)

A. CuSO4
B. Cu
C. H2SO4
D. H2

Respuesta :

Answer:

B. CU

Explanation:

Cu will be produced at the negative electrode for the following reaction:

2CuSO4 (a q) + 2H20 (1) -> 2Cu(s) + 2H2SO4(l) + O2(g) ,therefore option (b) is correct.

What do you mean by the term electrolysis ?

Electrolysis is defined as a process of decomposing ionic compounds into their elements by passing a direct electric current through the compound in a molten  form.

Characteristics of negative electrode -:


The negative electrode in an electrolytic cell, is the one toward which positively charged particles are attracted.

The cathode has a negative charge because it is connected to the negatively charged .

When an electrolyte is dissolved in water and an electric current is passed through it, the Cations move towards the cathode and Anions move towards anode .

Cu will be produced at the negative electrode for the following reaction:

2CuSO4 (a q) + 2H20 (1) -> 2Cu(s) + 2H2SO4(l) + O2(g) ,hence option (b) is correct.

Learn more about negative electrode ,here:

https://brainly.com/question/20350113

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