Question

Mr. Romeo wants to make a solution of NaOH. He measures out 97.68 grams and puts it into 3 liters

What is the molarity of the solution he created? Round to 2 Decimal points

Answer 1

Answer:  Molarity of the solution is 0.813 M.

Explanation:

Given : Mass of NaOH = 97.68 g

Volume of solution = 3 L

The molar mass of NaOH is 39.99 g/mol. Hence, moles of NaOH are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{97.68 g}{39.99 g/mol}\\= 2.44 mol$

Molarity is the number of moles of solute present in a liter of solution. Therefore, molarity of given solution is calculated as follows.

$Molarity = \frac{no. of moles of solute}{Volume (in L)}\\= \frac{2.44 mol}{3 L}\\= 0.813 M$

Thus, we can conclude that molarity of the solution is 0.813 M.