At a certain temperature the rate of this reaction is first order in HI with a rate constant of 0.0632 s
2HI g = H2 g + I2 g
Suppose a vessel contains HI at a concentration of 1.28M. Calculate how long it takes for the concentration of HI to decrease to 17.0% of its initial value.

Respuesta :

Answer:

[tex]28.037\ \text{s}[/tex]

Explanation:

[tex][A]_0[/tex] = Initial concentration = 1.28 M

[tex][A][/tex] = Final concentration = [tex]0.17[A]_0[/tex]

k = Rate constant = 0.0632 s

t = Time taken

For first order reaction we have the relation

[tex]kt=\ln\dfrac{[A]_0}{[A]}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{[A]}}{k}\\\Rightarrow t=\dfrac{\ln\dfrac{[A]_0}{0.17[A]_0}}{0.0632}\\\Rightarrow t=28.037\ \text{s}[/tex]

Time taken to reach the required concentration would be [tex]28.037\ \text{s}[/tex].

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