Answer:
[tex]4649.20\ \text{Hz}[/tex]
Explanation:
u = Speed of car = 65 mph
[tex]f_s[/tex] = Frequency of source = 24 GHz
c = Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]
Beat frequency or frequency shift between the observed (received) and source (transmitted) frequencies is given by
[tex]f_o-f_s=\dfrac{2uf_s}{c}\\\Rightarrow \Delta f=\dfrac{2\times 65\times \dfrac{1609.34}{3600}\times 24\times 10^9}{3\times 10^8}\\\Rightarrow \Delta f=4649.20\ \text{Hz}[/tex]
The difference between te required frequencies is [tex]4649.20\ \text{Hz}[/tex].