Question

(a) Solve the equation 4 cos x + 2 = 3 for 0° < x < 360°.

Answer 1

Answer:

divide both sides by cosx

4 sinx/cosx = 1

4 tanx = 1

tanx = 1/4

x = arctan(1/4) = 14.04°

but the tangent is also positive in quad III

so x = 180+14.04 = 194.04°

x = 14.04° or 194.04°

Step-by-step explanation:

do by this step

Answer 2

The value of x is 75.52°.

What is trigonometry?

Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.

For the given situation,

The equation is 4 cos x + 2 = 3 for 0° < x < 360°.

⇒ $4cosx=3-2$

⇒ $4cosx=1$

⇒ $cosx=\frac{1}{4}$

⇒ $x=cos^{-1} (\frac{1}{4} )$

⇒ $x=75.52$

Hence we can conclude that the value of x is 75.52°.

Learn more about trigonometry here

https://brainly.com/question/16965914

#SPJ2