Respuesta :
Answer:
a) W = - 1.92 10⁻¹⁸ J, b) U = 1.92 10⁻¹⁸ J, c) v = 2.05 10⁶ m / s
Explanation:
a) Work is defined by
W = F. x
the electric force is
F = q E
we substitute
W = q E x
where the displacement is parallel to the electric field
all quantities must be in the SI system
x = 3.20 cm = 0.0320 m
W = - 1.6 10-19 375 0.0320
W = - 1.92 10⁻¹⁸ J
b) potential energy
U = [tex]k \frac{q_1q_2}{r}[/tex]
the electrical power is
V = k q₁ / r
we can write this potential as a function of the electric field
V = -E x
we substitute
U = -q E x
U = - (-1.6 10⁻¹⁹) 375 0.0320
U = 1.92 10⁻¹⁸ J
Observe that the variation of the red potential is equal to the electrical work
c) let's use conservation of energy
starting point
Em₀ = U = e E x
final point
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
e E x = ½ m v²
v² = 2 e E x / m
v = [tex]\sqrt{ \frac{{2 \ 1.6 10^{-19} \ 375 \ 0.0320 } }{9.1 \ 10^{-31} } }[/tex]
v = [tex]\sqrt{4.2198 \ 10^{12}}[/tex]
v = 2.05 10⁶ m / s
