Answer:
[tex]Pr = \frac{1}{26}[/tex]
Step-by-step explanation:
Given
In a deck of card, we have:
[tex]Cards = 52[/tex]
[tex]King[Heart] = 1[/tex]
[tex]Queen[Spade] = 1[/tex]
Required
The probability of obtaining a king of heart or a queen of spade.
The probability of king of heart is:
[tex]P(King[Heart]) = \frac{n(King[Heart])}{Cards}[/tex]
[tex]P(King[Heart]) = \frac{1}{52}[/tex]
The probability of queen of spade is:
[tex]P(Queen[Spade]) = \frac{n(Queen[Spade])}{Cards}[/tex]
[tex]P(Queen[Spade]) = \frac{1}{52}[/tex]
The required probability of obtaining a king of heart or a queen of spade. is:
[tex]Pr = P(King[Heart]) + P(Queen[Spade])[/tex]
[tex]Pr = \frac{1}{52}+ \frac{1}{52}[/tex]
Take LCM
[tex]Pr = \frac{1+1}{52}[/tex]
[tex]Pr = \frac{2}{52}[/tex]
Simplify
[tex]Pr = \frac{1}{26}[/tex]
