Question

The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye
is viewed in a concave mirror with a radius of curvature equal to the diameter
of the eye and the eye is 0.800 × 10^3 mm from the mirror, how far is the image
from the mirror? What is the size of the image? Is the image real or virtual?​

Answer 1

Answer:

   q = 224 mm,   h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

        $\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

       

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

        f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

       R = 3,50  10² mm

       f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 175 - 1 /800

        1 / q = 0.004464

         q = 224 mm

to calculate the size let's use the magnification ratio

          m = $\frac{h'}{h} = - \frac{q}{p}$

          h '= $- \frac{q}{p} \ h$

          h ’= - 224 350 / 800

          h ’= - 98 mm

in concave mirrors the image is real.