Respuesta :
Answer:
19.06
Step-by-step explanation:
Put the points into the distance formula:
[tex]d=\sqrt{(-4-5)^2+(6-5)^2}[/tex]
Solve:
[tex]d=\sqrt{(-9)^2+(1)^2}[/tex]
[tex]d=\sqrt{82}[/tex]
[tex]d=9.055385[/tex]
Answer:
[tex]\displaystyle d = \sqrt{82}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
Algebra I
- Coordinates (x, y)
Algebra II
- Distance Formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Point (5, 5)
Point (-4, 6)
Step 2: Solve for d
Simply plug in the 2 coordinates into the distance formula to find distance d
- Substitute in coordinates [Distance Formula]: [tex]\displaystyle d = \sqrt{(-4-5)^2+(6-5)^2}[/tex]
- [Distance] [√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{(-9)^2+(1)^2}[/tex]
- [Distance] [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{81+1}[/tex]
- [Distance] [√Radical] Add: [tex]\displaystyle d = \sqrt{82}[/tex]