Answer:
B
Step-by-step explanation:
step 1 - rationalize the denominator to get:
[tex]\sqrt{35x^5}[/tex] ÷ [tex]\sqrt{7x^3}[/tex] = ([tex]\sqrt{245}[/tex] ·x^5/2·x^3/2) ÷ 7x³
= ([tex]\sqrt{5}[/tex][tex]\sqrt{7}[/tex][tex]\sqrt{7}[/tex]·x^4) ÷ 7x³
= 7[tex]\sqrt{5}[/tex]·x^4 ÷ 7x³
= [tex]\sqrt{5}[/tex]x
