Respuesta :

Answer:

Consider points (-3,6) and (0,5)

[tex]gradient \: \: m = \frac{(6 - 5)}{( - 3 - 0)} \\ m = - \frac{1}{3} \\ for \: perpendicular \: gradient \: m {}^{.} \\ m {}^{.} \times m = - 1 \\ - \frac{1}{3} m {}^{.} = - 1 \\ m {}^{.} = 3 \\ from \: y = mx + c \\ at \:(0,5) \: \: 5 = 0 \times 3 + c \\ c = 5 \\ hence \: equation \: is \: \: y = 3x + 5 [/tex]

Step-by-step explanation:

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