Question

In the diagram, AP is a tangent and PBC is a secant in a circle O. If PC = 12 and BC = 9, what is AP?

Answer 1

Answer:

6

Step-by-step explanation:

AP^2 = PC * PB

We have PC and BC. We need PB.

PC = 12

BC = 9

PB + BC = PC

PB + 9 = 12

PB = 3

AP^2 = 12 * 3

AP^2 = 36

AP = 6

Answer: 6

Answer 2

Answer:

Hey!

AP will be 6cm.

Step-by-step explanation:-

to solve this, the equation  PB X PC = $AP^{2}$  can be used

In the ques, its given that PC= 12cm and BC = 9.

To solve this, WE NEED TO FIND PB, SO:-

PB + BC = PC

PB + 9 = 12

PB = 3cm.

Now, we can substitute this in the equation:- PB X PC = $AP^{2}$

$AP^{2}$ = PB x PC

$AP^{2}$ = 3 X 12

$AP^{2}$ = 36

AP = $\sqrt{36}$

AP = 6cm.