Respuesta :
Answer:
0.1g (Gallon) of chlorine
Explanation:
Formula
1 gallon = 3.7L; the density of water is 1.0g/ml
Given
2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water
Solve
If 2g (gallon) chlorine = 1,000,000g (gallon)
∴, ? chlorine = 40,000
The First step; set up an equation
1000000/2 = 40000/?
The Next step; divide 1 million to 2
1000000 ÷ 2 = 500000
Then, divide the result by 40000
40000 ÷ 500000 = 0.08
In the nearest unit that is 0.1
Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.
Answer:
296
Explanation:
1 gallon = 3.7 L
40,000 gallon
= 40,000 × 3.7
= 148,000 L
1 g = 1 / 1000 L
1,000,000 g
= 1,000,000 / 1000
= 1,000 L
Let x be the amount of chlorine that will it take to sanitize a 40,000-gallon pool.
2 : 1,000 : : x : 148,000
2 / 1,000 = x / 148,000
x × 1,000 = 2 × 148,000
x = ( 2 × 148,000 ) / 1,000
= 2 × 148
x = 296 g
Therefore,
296 g of chlorine will it take to sanitize a 40,000-gallon pool.
( I solved using maths )