Question

A car accelerates uniformly from rest at a speed of 1.67 ft s^2 over a distance of 5 yards.What is the acceleration of a car?

Answer 1

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

Answer 2

Answer:

a=  0.256 ft/s^2

Explanation:

Solution:

Since the car has started from rest the initial velocity will be zero

i.e. Vi=0

It gets a speed of 1.6 fts^2,

i.e. Vf=  1.6 fts^2

The distance is 5 yards

i.e d= 5 yards

According to the equation of motion

2as= VF^2- Vi^2

Thus a=  (VF^2- Vi^2)/2s

a=  (1.6^2 - 0)/ 2*5

a=  0.256 ft/s^2