Answer:
[tex]\frac{2}{3}[/tex] hours
Step-by-step explanation:
Let [tex]t[/tex] be equal to the time that passes for Car A and Car B to be 8 km apart.
Let [tex]A[/tex] be equal to the distance that Car A travels within [tex]t[/tex].
Let [tex]B[/tex] be equal to the distance that Car B travels within [tex]t[/tex].
1) Create equations
[tex]Distance = Time*Velocity[/tex]
Therefore:
[tex]A=60t[/tex]
[tex]B=72t[/tex]
We also know that the distance between the two cars would be 8 km. Therefore:
[tex]B-A=8[/tex]
2) Solve for t (the time it takes for Car A and Car B to be 8 km apart)
Plug [tex]A=60t[/tex] and [tex]B=72t[/tex] into [tex]B-A=8[/tex]
[tex]72t-60t=8\\12t=8\\t=\frac{8}{12} \\t=\frac{2}{3}[/tex]
Because the velocity unit is km/h, we know that t will be in hours. Therefore, Car A and Car B were 8 km apart after [tex]\frac{2}{3}[/tex] hours.
I hope this helps!