Given:
The function is:
[tex]y=-(2x-4)(x-2)[/tex]
To find:
The x-intercepts and zeros of the given function.
Solution:
We have,
[tex]y=-(2x-4)(x-2)[/tex]
For x-intercepts, [tex]y=0[/tex].
[tex]-(2x-4)(x-2)=0[/tex]
[tex](2x-4)(x-2)=0[/tex]
Using zero product property, we get
[tex](2x-4)=0[/tex] and [tex](x-2)=0[/tex]
[tex]2x=4[/tex] and [tex]x=2[/tex]
[tex]x=\dfrac{4}{2}[/tex] and [tex]x=2[/tex]
[tex]x=2[/tex] and [tex]x=2[/tex]
The given function has two equal zeroes or x-intercept, i.e., [tex]x=2[/tex].
Therefore, the zeroes are 2 and 2.
Note: All options are incorrect.