Please help me with this.
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Given:
The quadratic equation is:
[tex]3x^2-5x-2=0[/tex]
To find:
Point that is the solution of given equation.
Solution:
We have,
[tex]3x^2-5x-2=0[/tex]
The quadratic function of the above equation is:
[tex]y=3x^2-5x-2[/tex]
Putting [tex]x=1[/tex], we get
[tex]y=3(1)^2-5(1)-2[/tex]
[tex]y=3-5-2[/tex]
[tex]y=-4[/tex]
The function passes through the point (1,-4). It means (1,-4) is the solution of given equation but (1,5) is not a solution of given equation.
Therefore, the correct option is A.