Question

A 42.2 N force acts at 40* to the ground, causing the object to move a horizontal distance of 8.15 m. How much work was done on the object?

Answer 1

Answer:

W=F.dcos angle

w=42.2 x8.15 x cos40

w=343.93× cos 40

W=343.93 x 0.76

W=261.38 J

Answer 2

Work done on the object will be 264.83 J

What is work done ?

Work done  is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.

given :

F = 42.2 N

let , x  = 40°

horizontal distance (s) = 8.15 m

Work done = F s cos (x)

                  = F * s * cos (x)

                  = 42.2 * 8.15 * cos 40° = .766

                  =  343.93 * 0.77

                  = 264.83 J

Work done on the object will be 264.83 J

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