Question

Calculate the grams of solute in each of the following solution: 278 mL of 0.038 M Fe2(SO4)3

Answer 1

Answer:

278 mL x 0.038 M = 10,564 mmol.

Using the molair mass of Fe2(SO4)3 to convert mmol to grams:

10,564 mmol / 1000 x 399,88 g/mol = 4,22 g Fe2(SO4)3.