hamad209 hamad209

18-04-2021
Physics

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When the car engine is working normally, 2 kg of coolant passes through the radiator each second. The temperature of the coolant falls from 112 °C to 97 °C. Calculate the energy transferred each second from the coolant. Specific heat capacity of the coolant = 3800 J/kg °C

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keijosalonen keijosalonen

18-04-2021

Answer: 114 kJ/s

Explanation: Q = mcΔT = 2 kg · 3800 J/(kg C) ·15 C

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