Question

find the angle of elevation of a kite on a 50m
string flying 40m vertically above the ground.

Answer 1

sin(x)=40/50
x= sin^-1(40/50)
x= 53.1301023542—>53.1 rounded to the nearest tenth
angle of elevation is 53.1

Answer 2

The angle of elevation of a kite is 53.13°

What is angle of elevation?

"It is the angle formed by the line of sight and the horizontal plane for an object above the horizontal surface."

What is sine angle?

"For a right triangle, the sine of acute angle $\theta$ is,

$sin(\theta)=\frac{opposite ~side}{hypotenuse}$"

For given question,

Consider the following diagram for given question.

The length of the string (AC) = 50m

The kite is flying 40m vertically above the ground.

⇒AB = 40m

We need to find the angle of elevation $\theta$

Consider the sine of angle  $\theta$

$\Rightarrow sin(\theta)=\frac{AB}{AC} \\\\\Rightarrow sin(\theta)=\frac{40}{50}\\\\\Rightarrow sin(\theta)=0.8\\\\\Rightarrow \theta=sin^{-1}(0.8)\\\\\Rightarrow \theta=53.13^{\circ}$

Therefore, the angle of elevation of a kite is 53.13°

Learn more about the angle of elevation here:

https://brainly.com/question/21137209

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