Question

Steve and Meg are doing an experiment where they need to make 37 grams of Fe2O3. How many grams of Fe would they need ?

Answer 1

Answer:

25.9g

Explanation:

Molecular mass of Fe₂O₃ = (56 * 2) + (16 * 3)

                                          = 112 + 48 = 160

Let's follow the unitary method now

In 160g Fe₂O₃ , there is 112 g Fe

In 1 g  Fe₂O₃ , there is 112 / 160 g Fe

In 37  Fe₂O₃ , we need 112 * 37 / 160

= 25.9 g Fe