Question

a sample of 0.0084 mol of HCl is dissolved in water to make a 1500 mL solution. calculate the molar it’s of the HCl solution, The H3O, and the pH

Answer 1

Answer:

pH = 2.25

Explanation:

pH is a measurement in chemistry defined as the -log [H₃O⁺]. Molarity [], is defined as the ratio between moles of solute (HCl) and the liters of solution

To solve this question we must find the molarity of the H₃O⁺ knowing: [HCl] = [H₃O⁺]

[HCl]:

0.0084moles / 1.500L

= 0.0056M = [HCl] = [H₃O⁺]

pH = -log [H₃O⁺] = -log [0.0056M]

pH = 2.25

Answer 2

A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a molar concentration of HCl of 5.6 × 10⁻³ M, a molar concentration of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.

A solution is prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution. The molarity of HCl is:

$[HCl] = \frac{0.0084mol}{1.5L} = 5.6 \times 10^{-3} M$

HCl is a strong acid according to the following equation.

HCl(aq) + H₂O(l) ⇒ Cl⁻(aq) + H₃O⁺(aq)

Thus, the concentration of H₃O⁺ will be equal to the initial concentration of HCl, 5.6 × 10⁻³ M.

Finally, we will calculate the pH of the solution using its definition.

$pH = -log [H_3O^{+} ] = -log (5.6 \times 10^{-3} ) = 2.3$

A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a molar concentration of HCl of 5.6 × 10⁻³ M, a molar concentration of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.

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