Question

Part
A certain gas is present in a 110 L cylinder at 2.0 atm pressure. If the pressure is increased to 4.0 atm, the volume of the gas
decreases to 5.5 L. Find the two constants k. the initial value of k, and kr, the final value of k, to verify whether the gas obeys Boyle's
law.
Express your answers to two significant figures separated by a comma.
View Available Hint(s)
ΤΟ
ΑΣΦ
t
2) ?
k ke =
Submit

Answer 1

Answer:

See explanation

Explanation:

Recall that from Boyle's law;

Volume is inversely proportional to pressure at constant temperature

V α 1/P

V = k/P

k = PV

Hence, for Boyle's law, PV = constant

In the first case;

P = 2.0 atm , V= 110 L

PV = 110 * 2.0 = 220

In the second case;

P = 4.0 atm , V= 5.5 L

PV = 4.0 * 5.5 = 22

Since PV is not constant in both cases, the gas does not obey Boyle's law.