Answer: The sample absorbed 3061.565J
Explanation:
Given that
Mass of water = 335g
Initial temperature = 24.5°C
Final temperature = 26.4°C
Heat absorbed by the sample is given as = mass x specific heat of water x temperature change
Heat absorbed,q=mCΔt
The specific heat of water,C = 4.81J/g°C
Therefore, Heat absorbed,q = 335 x 4.81h x (26.4 - 24.5) = 3061.565J
Answer:
2660.57 J
Explanation:
26.4 - 24.5 = 1.9
335 x 4.18 x 1.9 = 2660.57 J
That is the correct answer.
