Question

write a quadratic function in the given form whose graph satisfies the given condition.

has a vertex of (5, -2) & passes through the point (3, 6) in vertex form

pls help...important...dont steal

Answer 1

Answer:

f(x) = 2(x-5)²-2

Step-by-step explanation:

The equation of a parabola in vertex form is y=a(x-h)²+k where (h,k) is the vertex and "a" represents how stretched or compressed the parabola is and what direction it travels.

Given a vertex of (5,-2) the equation so far is y=a(x-5)²-2

Since we want the parabola to pass through the point (3,6) we must find a value of "a" that satisfies this:

y=a(x-5)²-2

6=a(3-5)²-2

6=a(-2)²-2

6=4a-2

8=4a

2=a

This means that the quadratic function is f(x) = 2(x-5)²-2