Based on a poll of 1000 residents, a newspaper article claims that 62% of the residents in town favor the development of a recreational
park on the west side of town. A community action group interested in preserving the environment claims that 45% of the town's
residents favor the development of a recreational park.
To determine whether the sample supports the
population proportion, a simulation of 100 trials is run, each with a
sample of 200, using the point estimate of the population. The minimum sample proportion from the simulation is 0.46 and the
maximum sample proportion is 0.76.
What is the point estimate of the population?
The margin of error of the population proportion is found using an estimate of the standard deviation. What is the
interval estimate of the true population proportion?
The margin of error of the population proportion is found using the half the range.
What is the interval estimate of the true population proportion?
Is the community action group's claim likely based on either interval estimate of the true population proportion?
Explain.

Divide the number of events by the number of possible outcomes. After determining the probability event and its corresponding outcomes, divide the total number of ways the event can occur by the total number of possible outcomes.

a. The point estimate of the population will be calculated thus:

= 62% = 62/100 = 0.62

b. The margin of error of the population will be:

= z value × [✓0.62 × ✓0.38 / ✓200]

= 1.96 × (0.78 × 0.61 / 14.14)

= 0.0672

Therefore, the interval estimate is 6.72%.

c. The margin of error of the population proportion is found using half the range will be:

= [0.76 - 0.46] /2

= 0.30/2

= 0.15

d. The community action group’s claim is likely based on either interval estimate of the true population proportion since the confidence interval value is greater than 0.45.

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