Answer:
2L of nitrogen gas will be needed
Explanation:
Based on the following reaction:
N₂ + 3H₂ → 2NH₃
1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.
If 6L of hydrogen (In a gas, the volume is directly proportional to the moles, Avogadro's law) react, the volume of nitrogen gas required will be:
6L H₂ * (1mol N₂ / 3 moles H₂) =
2L of nitrogen gas will be needed
