avacats2004 avacats2004
  • 16-04-2021
  • Mathematics
contestada

8m^3 - 28m^2 + 6m - 21. You solve by factoring by grouping!!! quick please

Respuesta :

Hrishii
Hrishii Hrishii
  • 16-04-2021

Answer:

[tex] (2m - 7)(4 {m}^{2} + 3)[/tex]

Step-by-step explanation:

[tex]8m^3 - 28m^2 + 6m - 21 \\ = 4 {m}^{2} (2 {m} - 7) + 3(2m - 7) \\ = (2m - 7)(4 {m}^{2} + 3)[/tex]

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