through (2, 5); perpendicular to y = (-2/7)x - 3
first, you should know that the slopes of parallel lines are the same. the slopes of perpendicular lines are opposite reciprocals of one another. in this case, because you need to find a perpendicular line, you'll want to find the opposite reciprocal of (-2/7)
change the sign and flip the fraction: your new slope is 7/2
from there, you just plug it into point-slope form:
y - y1 = m(x - x1)
y - 5 = (7/2)(x - 2)
then you can solve it further to bring it into slope-intercept (y = mx + b):
y - 5 = (7/2)(x - 2)
y - 5 = (7/2)x - 7
y = (7/2)x - 2 is your answer.
