Answer:
Following are the responses to the given question:
Step-by-step explanation:
[tex]Null \ H_{yp}: \mu_{men} = \mu_{women}\\\\Alt \ Hyp: \mu_{men} \neq \mu_{women}\\\\Std\ Error\ (SE) = \sqrt{(\frac{s_1^2}{n_1}) + (\frac{s_2^2}{n_2})} \\\\[/tex]
[tex]= \sqrt{(\frac{0.62}{90}) + (\frac{0.52}{100})} \\\\= 0.08[/tex]
[tex]test\ statistic \ t = \frac{(x_1 - x_2)}{SE} = \frac{(8.4 - 8.5)}{0.08} = -1.25[/tex]
Degrees of freedom
[tex]= \frac{(\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2})^2}{\frac{(\frac{s_1^2}{n_1})^2}{(n_1 - 1)}} + \frac{(\frac{s_2^2}{n_2)^2}}{(n_2 - 1)} \\\\= 174[/tex]
Considering a degree of 5% importance
T for df critical value = 174 and sig level = 0.05 is +1.973
Let area of refusal shall be t < -1.973 or t > +1.973
Because statistical tests weren't in the refusal zone, they may not deny that zero but find that perhaps the argument how both women and men undergo med school is considerably different lengths of time is not significantly supported.