Respuesta :
Answer:
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.
Explanation:
Let suppose that vehicle is moving at constant velocity. By Newton's Law of Motion, the force given by engine must be equal to the sum of the rolling resistance and the aerodynamic drag force of the air. And by definition of power, we have the following formula:
[tex]\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v[/tex] (1)
Where:
[tex]\dot W[/tex]- Power, in pounds-force-feet per second.
[tex]f[/tex] - Rolling resistance coefficient, no unit.
[tex]W[/tex] - Weight of the passanger car, in pounds-force.
[tex]\rho[/tex] - Density of air, in pounds-mass per cubic feet.
[tex]C_{D}[/tex] - Drag coefficient, no unit.
[tex]A[/tex] - Projected frontal area, in square feet.
[tex]v[/tex] - Vehicle speed, in feet per second.
[tex]g_{c}[/tex] - Pound-mass to pound-force ratio, in pounds-mass to pound-force.
If we know that [tex]f = 0.02[/tex], [tex]W = 3,550\,lbf[/tex], [tex]\rho = 0.08\,\frac{lbm}{ft^{3}}[/tex], [tex]C_{D} = 0.34[/tex], [tex]A = 23.3\,ft^{2}[/tex], [tex]v = 80.685\,\frac{ft}{s}[/tex] and [tex]g_{c} = 32.174\,\frac{lbm}{lbf}[/tex], then the power required by the car is:
[tex]\dot W = \left(f\cdot W +\frac{\rho\cdot C_{D}\cdot A\cdot v^{2}}{2\cdot g_{c}} \right)\cdot v[/tex]
[tex]\dot W = 10901.941\,\frac{lbf\cdot ft}{s}[/tex]
[tex]\dot W = 19.623\,h.p.[/tex]
The power required to overcome rolling resistance and aerodynamic drag is 19.623 h.p.