Question

What is the molarity of a solution that contains
92 grams of Ca(NO3)2 (molar mass = 164 g/mol)
in 0.4 liter of solution?
Please help! Quickly!

Answer 1

Explanation:

no. of molea of Ca(NO3)2 = given mass/molar mass

no. of moles= 92/ 164 = 0.56 mol

formula=

Molarity = moles of solute /solution in litres

Molarity = 0.56/ 0.4

=1.4 M

hope it helped!