Question

can someone pls help!!

Answer 1

Answer:

$y=-\frac{1}{9}(x-2)^2-3$

Step-by-step explanation:

When a quadratic equation is in the form $y=a(x-h)^2+k$ (vertex form):

1. The x-coordinate can be found by identifying which value makes $(x-h)^2$ equal 0
2. The y-coordinate can be found by identifying the k value (y=k)

Therefore, if the vertex of the function is at (2,-3), h needs to be 2 for $(x-h)^2$  to equal 0 and k needs to be -3. The only equation that displays this is G:

$y=-\frac{1}{9}(x-2)^2-3$

I hope this helps!