Question

A research submarine has a 30-cm-diameter window that is 8.6 cm thick. The manufacturer says the window can withstand forces up to 1.2×106 N .

What is the submarine's maximum safe depth in sea water? The pressure inside the submarine is maintained at 1.0 atm.
Express your answer using two significant figures.

Answer 1

First solve the area of the ow the window os the submarine

A = pi* (0.15)^2= 0.0707 m2

The pressure it can with stand is

P= F/A = 1.2x10^6 N/ 0.0707 m2 = 16976527.26 Pa

Using the formala

P = pgh

Where p is the density of water

G is the accelartion due to gravity

H is the depth

H = P/pg

=16976527.26 Pa/ (1000 kg/m3)(9.81 m/s2)

H = 1730.53 m