Answer:
126
AS:
If these cubes are to to be placed so that their respective faces are parallel
or perpendicular, as the case may be, to the respective orientations of the
dimensions of the box, without tilting any cubes in any directions,
then choice B) can be justified. This leaves spaces (some volume) in the box
not filled by the cubes.
How many whole number of edges of the cubes fit into 4 cm?
4
/
3
√
2 must be rounded down to 3.
How many whole number of edges of the cubes fit into 8 cm?
8
/
3
√
2 must be rounded down to 6.
How many whole number of edges of the cubes fit into 10 cm?
10
/
3
√
2 must be rounded down to 7.
Then (3)(6)(7) = 126
