95.8% is the percent yield for sodium chloride if 56.0 g of sodium chloride is produced in the reaction.
How we calculate the percentage yield?
Percentage yield of any chemical reaction can be calculated as:
% yield = (Experimental yield/Theoretical yield) × 100
Given chemical reaction is:
NaHCO₃ + HCl → NaCl + CO₂ + H₂O
In the question it is given that 56 grams of NaCl is produced by mass. But according to the stoichiometry of the reaction 1 mole of NaCl will be produced whose mass should be 58.44 grams. So, % yield will be:
% yield = (56/58.44) × 100 = 95.8%
Hence, option (d) is correct it means 95.8% is the percent yield.
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https://brainly.com/question/8638404
