Question

A 2.5 V battery is connected to a small light
bulb with a resistance of 4.8 Ω .
What is the current in the bulb?
Answer in units of A.

Answer 1

Answer: I=0.52 A

Explanation:

Given

Voltage is $2.5\ V$

Resistance $R=4.8\ \Omega$

Current is given by

$I=\dfrac{V}{R}$

$\Rightarrow I=\dfrac{2.5}{4.8}=0.52\ A$